Specific Heat lab

Question: Find a method to find the redundant waken capacity of an foreign object. Hypothesis: Using the analyse q=mc∆T, the heat capacity of the un be intimaten object clear(p) fire be go downd. Assuming heat expiry by piddle = heat gained by the object, we can function two concurrent equations to solve for the c value of the object. Variables: Controlled quantify for irrigate to cool, nap of metal, volume of water Dependent revision in temperature Materials: Hot plate The extraterrestrial object Thermometer trade balance Calorimeter Water Beaker Procedure: 1.Carefully measure 200 mL of water for the beaker and the calorimeter. 2.Note down the water in twain containers 3.weigh the abstruse object using the mass balance 4. bottom the unknown object in the beaker with the water. 5.Heat the water in the beaker until it boils. 6.Remove the object from the beaker and vomit up it into the calorimeter filled with water. 7.Cover the eyelid and place the thermometer inside to measure the temperature change. data Collection: trial #1: Mass of the unknown objectInitial temperature T1 (◦C) ± 0.5 illuminate temperature T2 (◦C) ± 0.5 Calorimeter 200mL of water2032 Beaker 200mL of H2O2086 Trial #2: Mass of the unknown objectInitial temperature T1 (◦C) ± 0.

5Final temperature T2 (◦C) ± 0.5 Calorimeter 200mL of H2O2029 Beaker 200mL of H2O2087 Data bear upon: We know that the heat lost by the water is get even to the heat gained by the unknown object. Therefore mwcw∆Tw = mobjectcobject∆Tobject is true. Trial #1: mw = 200g cw = 4.18 kJ/kgK, ∆Tw = 97 20 = 77◦! ;C mobject = 21.7g cobject = ? ∆Tobject = 32 20 = 12◦C Therefore, (200)(4.18)(77) = (21.7)( cobject )(12) cobject = t1 = water t2 = water + metal destruction In this experiment, the change in the temperature of water was used to see to it the specific heat capacity of an unknown...If you want to get a full essay, order it on our website: OrderEssay.net

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